3x^2-2x-1680=0

Solution for 3x^2-2x-1680=0 equation:

3x^2-2x-1680=0

a = 3; b = -2; c = -1680;
Δ = b2-4ac
Δ = -22-4·3·(-1680)
Δ = 20164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20164}=142$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-142}{2*3}=\frac{-140}{6}
=-23+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+142}{2*3}=\frac{144}{6}
=24
$